Integrand size = 24, antiderivative size = 38 \[ \int \frac {d+e x}{\left (a^2+2 a b x+b^2 x^2\right )^3} \, dx=-\frac {b d-a e}{5 b^2 (a+b x)^5}-\frac {e}{4 b^2 (a+b x)^4} \]
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Time = 0.02 (sec) , antiderivative size = 38, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {27, 45} \[ \int \frac {d+e x}{\left (a^2+2 a b x+b^2 x^2\right )^3} \, dx=-\frac {b d-a e}{5 b^2 (a+b x)^5}-\frac {e}{4 b^2 (a+b x)^4} \]
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Rule 27
Rule 45
Rubi steps \begin{align*} \text {integral}& = \int \frac {d+e x}{(a+b x)^6} \, dx \\ & = \int \left (\frac {b d-a e}{b (a+b x)^6}+\frac {e}{b (a+b x)^5}\right ) \, dx \\ & = -\frac {b d-a e}{5 b^2 (a+b x)^5}-\frac {e}{4 b^2 (a+b x)^4} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.71 \[ \int \frac {d+e x}{\left (a^2+2 a b x+b^2 x^2\right )^3} \, dx=-\frac {4 b d+a e+5 b e x}{20 b^2 (a+b x)^5} \]
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Time = 2.43 (sec) , antiderivative size = 35, normalized size of antiderivative = 0.92
method | result | size |
default | \(-\frac {-a e +b d}{5 b^{2} \left (b x +a \right )^{5}}-\frac {e}{4 b^{2} \left (b x +a \right )^{4}}\) | \(35\) |
norman | \(\frac {-\frac {e x}{4 b}+\frac {-e a \,b^{3}-4 d \,b^{4}}{20 b^{5}}}{\left (b x +a \right )^{5}}\) | \(36\) |
gosper | \(-\frac {5 b e x +a e +4 b d}{20 b^{2} \left (b x +a \right ) \left (b^{2} x^{2}+2 a b x +a^{2}\right )^{2}}\) | \(44\) |
risch | \(\frac {-\frac {e x}{4 b}-\frac {a e +4 b d}{20 b^{2}}}{\left (b x +a \right ) \left (b^{2} x^{2}+2 a b x +a^{2}\right )^{2}}\) | \(48\) |
parallelrisch | \(\frac {-5 e x \,b^{4}-e a \,b^{3}-4 d \,b^{4}}{20 b^{5} \left (b^{2} x^{2}+2 a b x +a^{2}\right )^{2} \left (b x +a \right )}\) | \(52\) |
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Leaf count of result is larger than twice the leaf count of optimal. 72 vs. \(2 (34) = 68\).
Time = 0.29 (sec) , antiderivative size = 72, normalized size of antiderivative = 1.89 \[ \int \frac {d+e x}{\left (a^2+2 a b x+b^2 x^2\right )^3} \, dx=-\frac {5 \, b e x + 4 \, b d + a e}{20 \, {\left (b^{7} x^{5} + 5 \, a b^{6} x^{4} + 10 \, a^{2} b^{5} x^{3} + 10 \, a^{3} b^{4} x^{2} + 5 \, a^{4} b^{3} x + a^{5} b^{2}\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 76 vs. \(2 (32) = 64\).
Time = 0.28 (sec) , antiderivative size = 76, normalized size of antiderivative = 2.00 \[ \int \frac {d+e x}{\left (a^2+2 a b x+b^2 x^2\right )^3} \, dx=\frac {- a e - 4 b d - 5 b e x}{20 a^{5} b^{2} + 100 a^{4} b^{3} x + 200 a^{3} b^{4} x^{2} + 200 a^{2} b^{5} x^{3} + 100 a b^{6} x^{4} + 20 b^{7} x^{5}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 72 vs. \(2 (34) = 68\).
Time = 0.19 (sec) , antiderivative size = 72, normalized size of antiderivative = 1.89 \[ \int \frac {d+e x}{\left (a^2+2 a b x+b^2 x^2\right )^3} \, dx=-\frac {5 \, b e x + 4 \, b d + a e}{20 \, {\left (b^{7} x^{5} + 5 \, a b^{6} x^{4} + 10 \, a^{2} b^{5} x^{3} + 10 \, a^{3} b^{4} x^{2} + 5 \, a^{4} b^{3} x + a^{5} b^{2}\right )}} \]
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none
Time = 0.27 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.66 \[ \int \frac {d+e x}{\left (a^2+2 a b x+b^2 x^2\right )^3} \, dx=-\frac {5 \, b e x + 4 \, b d + a e}{20 \, {\left (b x + a\right )}^{5} b^{2}} \]
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Time = 0.05 (sec) , antiderivative size = 74, normalized size of antiderivative = 1.95 \[ \int \frac {d+e x}{\left (a^2+2 a b x+b^2 x^2\right )^3} \, dx=-\frac {\frac {a\,e+4\,b\,d}{20\,b^2}+\frac {e\,x}{4\,b}}{a^5+5\,a^4\,b\,x+10\,a^3\,b^2\,x^2+10\,a^2\,b^3\,x^3+5\,a\,b^4\,x^4+b^5\,x^5} \]
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